A block requires 26 N of force to get it moving and 15 N of force to keep it moving at constant velocity. If the static frictional coefficient is 0.77, what is the normal force and the kinetic frictio

The force required to get the block moving (static friction) is $F_s = 26 \text{ N}$.
The force required to keep the block moving at a constant velocity (kinetic friction) is $F_k = 15 \text{ N}$.
The static frictional coefficient is $\mu_s = 0.77$.

The formula for static friction is $F_s = \mu_s F_N$.
Rearrange to solve for $F_N$:

Substitute the values:

The formula for kinetic friction is $F_k = \mu_k F_N$.
Rearrange to solve for $\mu_k$:

Substitute the values:

The answers are:

3.1 Normal force exerted onto the block: $\boxed{\text{33.77 N}}$

3.2 Kinetic frictional coefficient: $\boxed{\text{0.44}}$