A car moving at 10 m/s accelerates uniformly and covers 180m in 10s. Calculate its acceleration and final velocity.

Given:
Initial velocity, $u = 10 \, \text{m/s}$
Distance, $s = 180 \, \text{m}$
Time, $t = 10 \, \text{s}$

We need to find the acceleration ($a$) and final velocity ($v$).
We will use the kinematic equations:

1. $s = ut + \frac{1}{2}at^2$
2. $v = u + at$

$$s = ut + \frac{1}{2}at^2$$

Substitute the given values:

$$180 \, \text{m} = (10 \, \text{m/s})(10 \, \text{s}) + \frac{1}{2}a(10 \, \text{s})^2$$ $$180 = 100 + \frac{1}{2}a(100)$$ $$180 = 100 + 50a$$

Subtract 100 from both sides:

$$180 - 100 = 50a$$ $$80 = 50a$$

Divide by 50 to find $a$:

$$a = \frac{80}{50}$$ $$a = 1.6 \, \text{m/s}^2$$

$$v = u + at$$

Substitute the initial velocity ($u$), acceleration ($a$), and time ($t$):

$$v = 10 \, \text{m/s} + (1.6 \, \text{m/s}^2)(10 \, \text{s})$$ $$v = 10 + 16$$ $$v = 26 \, \text{m/s}$$

The acceleration is $\boxed{1.6 \, \text{m/s}^2}$ and the final velocity is $\boxed{26 \, \text{m/s}}$.