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A coil of 500 turns has a magnetic flux of 0.4 Wb linking it. If this flux is reversed in 0.01 s, what is the induced EMF in the coil?

April 13, 2026Physics

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Answer

\text{40000 V}

3 steps

Identify the given values.
Number of turns, $N = 500$ .
Initial magnetic flux, $\Phi_1 = 0.4 \text{ Wb}$ .
Since the flux is reversed, the final magnetic flux, $\Phi_2 = -0.4 \text{ Wb}$ .
Time interval, $\Delta t = 0.01 \text{ s}$ .
Calculate the change in magnetic flux $\Delta \Phi$ .
$\Delta \Phi = \Phi_2 - \Phi_1$ $\Delta \Phi = (-0.4 \text{ Wb}) - (0.4 \text{ Wb})$ $\Delta \Phi = -0.8 \text{ Wb}$
Apply Faraday's Law of Induction to find the induced EMF $\mathcal{E}$ .
$\mathcal{E} = -N \frac{\Delta \Phi}{\Delta t}$ $\mathcal{E} = -(500) \times \frac{-0.8 \text{ Wb}}{0.01 \text{ s}}$ $\mathcal{E} = (500) \times \frac{0.8}{0.01} \text{ V}$ $\mathcal{E} = 500 \times 80 \text{ V}$ $\mathcal{E} = 40000 \text{ V}$
The induced EMF is $\text{40000 V}$ .