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A dentist is working on a patient in a reclining chair. The dentist moves at 0.5 m/s towards the patient, and the patient reclines backwards at 0.2 m/s. What is the dentist's speed relative to the pat

Physics

ScanSolve AI Answer

Answer

0.3 ms−1\text{0.3 ms}^{-1}

Step-by-step solution

3 steps
  1. Define the velocities with respect to the ground.

    Let's consider the direction from the patient towards the dentist as the positive direction.

    • Velocity of the dentist (vDv_D): The dentist moves towards the patient. This means the dentist is moving in the negative direction relative to our chosen positive direction. vD=−0.5 ms−1v_D = -0.5 \text{ ms}^{-1}
    • Velocity of the patient (vPv_P): The patient reclines backwards. This means the patient is moving away from the dentist, which is also in the negative direction. vP=−0.2 ms−1v_P = -0.2 \text{ ms}^{-1}
  2. Calculate the velocity of the dentist relative to the patient.

    The relative velocity of object A with respect to object B is given by vAB=vA−vBv_{AB} = v_A - v_B.
    Here, we want the velocity of the dentist relative to the patient (vDPv_{DP}).

    vDP=vD−vPv_{DP} = v_D - v_P

    Substitute the values:

    vDP=(−0.5 ms−1)−(−0.2 ms−1)v_{DP} = (-0.5 \text{ ms}^{-1}) - (-0.2 \text{ ms}^{-1}) vDP=−0.5 ms−1+0.2 ms−1v_{DP} = -0.5 \text{ ms}^{-1} + 0.2 \text{ ms}^{-1} vDP=−0.3 ms−1v_{DP} = -0.3 \text{ ms}^{-1}
  3. Determine the speed.

    Speed is the magnitude of velocity.

    Speed=∣vDP∣=∣−0.3 ms−1∣\text{Speed} = |v_{DP}| = |-0.3 \text{ ms}^{-1}| Speed=0.3 ms−1\text{Speed} = 0.3 \text{ ms}^{-1}

    The dentist's speed relative to the patient is 0.3 ms−1\text{0.3 ms}^{-1}.

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