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A force of 2 N is applied to a needle. What is the maximum area of the needle if the pressure is 2,000,000 Pa?

Physics

ScanSolve AI Answer

Answer

1×10−6 m2\text{1} \times 10^{-6} \, \text{m}^2

Step-by-step solution

5 steps
  1. Identify the given values.

    The force applied (FF) is 2 N2 \, \text{N}.
    The required pressure (PP) is 2,000,000 Pa2,000,000 \, \text{Pa}.

  2. Recall the formula for pressure.

    Pressure is defined as force per unit area:

    P=FAP = \frac{F}{A}

    where PP is pressure, FF is force, and AA is area.

  3. Rearrange the formula to solve for area.

    To find the area, we can rearrange the formula:

    A=FPA = \frac{F}{P}
  4. Substitute the given values into the formula.

    A=2 N2,000,000 PaA = \frac{2 \, \text{N}}{2,000,000 \, \text{Pa}}
  5. Calculate the area.

    A=0.000001 m2A = 0.000001 \, \text{m}^2

    This can also be expressed in scientific notation:

    A=1×10−6 m2A = 1 \times 10^{-6} \, \text{m}^2

    The maximum area of the needle must be 1×10−6 m2\text{1} \times 10^{-6} \, \text{m}^2.

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