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A gas occupies a volume of 2000 cm³ at a certain pressure. If the pressure is reduced to 1/5 of its original value while keeping the temperature constant, what is the new volume of the gas?

Physics

ScanSolve AI Answer

Answer

10000 cm3\text{}10000 \text{ cm}^3\text{}

Step-by-step solution

4 steps

This problem involves Boyle's Law, which states that for a fixed mass of gas at constant temperature, the pressure and volume are inversely proportional (P1V1=P2V2P_1 V_1 = P_2 V_2).

  1. Identify the given values.

    The initial volume is V1=2000 cm3V_1 = 2000 \text{ cm}^3.
    The new pressure is P2=15P1P_2 = \frac{1}{5} P_1.
    The temperature is constant.

  2. Apply Boyle's Law.

    P1V1=P2V2P_1 V_1 = P_2 V_2
  3. Substitute the known values into the equation.

    P1×2000 cm3=(15P1)×V2P_1 \times 2000 \text{ cm}^3 = \left(\frac{1}{5} P_1\right) \times V_2
  4. Solve for the new volume, V2V_2.

    Divide both sides by P1P_1:

    2000 cm3=15V22000 \text{ cm}^3 = \frac{1}{5} V_2

    Multiply both sides by 5:

    V2=5×2000 cm3V_2 = 5 \times 2000 \text{ cm}^3 V2=10000 cm3V_2 = 10000 \text{ cm}^3

    The new volume is 10000 cm3\text{}10000 \text{ cm}^3\text{}

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