This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's the solution for question 6: 6. When the pressure on 200 cm^3 of a gas is doubled, and its absolute temperature is halved, its volume would become Step 1: State the combined gas law formula. The combined gas law relates pressure, volume, and absolute temperature for a fixed amount of gas: (P_1V_1)/(T_1) = (P_2V_2)/(T_2) where P is pressure, V is volume, and T is absolute temperature. Step 2: Identify the initial and final conditions from the problem statement. Initial volume V_1 = 200 cm^3. Let initial pressure P_1 = P. Let initial absolute temperature T_1 = T. The pressure is doubled, so final pressure P_2 = 2P. The absolute temperature is halved, so final absolute temperature T_2 = (T)/(2). We need to find the final volume V_2. Step 3: Substitute these values into the combined gas law equation. P · 200 cm^3T = ((2P) · V_2)/((T/2)) Step 4: Simplify the equation to solve for V_2. First, simplify the right side of the equation: P · 200 cm^3T = (2P · V_2 · 2)/(T) P · 200 cm^3T = (4P · V_2)/(T) Now, multiply both sides by T and divide by P: 200 cm^3 = 4V_2 V_2 = 200 cm^34 V_2 = 50 cm^3 The correct option is C. C) 50 cm^3 That's 2 down. 3 left today — send the next one.