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A gas in a container has a volume of 2000 cm3. If the pressure is reduced to 1/5 of its original pressure while the temperature remains constant, what is the new volume?

Physics

ScanSolve AI Answer

Answer

10000 cm3\text{10000 cm}^3

Step-by-step solution

4 steps
  1. Identify the given values and the relevant gas law.

    The problem describes a fixed mass of gas at a constant temperature, which means Boyle's Law applies.
    Initial volume, V1=2000 cm3V_1 = 2000 \text{ cm}^3.
    The new pressure, P2P_2, is 15\frac{1}{5} of the original pressure, P1P_1. So, P2=15P1P_2 = \frac{1}{5} P_1.
    We need to find the new volume, V2V_2.

  2. State Boyle's Law.

    Boyle's Law states that for a fixed mass of gas at constant temperature, the product of pressure and volume is constant:

    P1V1=P2V2P_1 V_1 = P_2 V_2
  3. Substitute the known values into the equation.

    P1×2000 cm3=(15P1)×V2P_1 \times 2000 \text{ cm}^3 = \left(\frac{1}{5} P_1\right) \times V_2
  4. Solve for V2V_2.

    Divide both sides by P1P_1:

    2000 cm3=15V22000 \text{ cm}^3 = \frac{1}{5} V_2

    Multiply both sides by 5:

    V2=5×2000 cm3V_2 = 5 \times 2000 \text{ cm}^3 V2=10000 cm3V_2 = 10000 \text{ cm}^3

    The new volume is 10000 cm3\text{10000 cm}^3.

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