A glass flask has a capacity of 60 cm³ at 12 °C. Calculate the capacity of the flask at a temperature of 50 °C if the glass has a linear coefficient of expansion of 9 × 10⁻⁶/°C.

Here's the solution for question 2: Given: Initial volume of glass vessel (V_0) = 60 cm^3 Initial temperature (T_0) = 18 °C Final temperature (T_f) = 60 °C Linear coefficient of expansion of glass (_g) = 9 × 10^-6 /°C Volumetric expansion coefficient of mercury (_m) = 180 × 10^-6 /°C Step 1: Calculate the change in temperature ( T). T = T_f - T_0 = 60 °C - 18 °C = 42 °C a) The volume of the glass vessel at 60 °C. Step 2: Calculate the volumetric expansion coefficient of glass (_g). The volumetric expansion coefficient is approximately three times the linear expansion coefficient. _g = 3 _g = 3 × (9 × 10^-6 /°C) = 27 × 10^-6 /°C Step 3: Calculate the change in volume of the glass vessel ( V_g). V_g = V_0 _g T V_g = (60 cm^3) × (27 × 10^-6 /°C) × (42 °C) V_g = 0.06804 cm^3 Step 4: Calculate the final volume of the glass vessel (V_f,g). V_f,g = V_0 + V_g = 60 cm^3 + 0.06804 cm^3 V_f,g = 60.06804 cm^3 b) The absolute expansion of mercury. Step 5: Calculate the absolute change in volume of mercury ( V_m). The initial volume of mercury is the same as the initial volume of the vessel, V_0 = 60 cm^3. V_m = V_0 _m T V_m = (60 cm^3) × (180 × 10^-6 /°C) × (42 °C) V_m = 0.4536 cm^3 V_m = 0.4536 cm^3 c) The apparent expansion of the mercury. Step 6: Calculate the apparent expansion of mercury ( V_app). The apparent expansion is the difference between the absolute expansion of mercury and the expansion of the glass vessel. V_app = V_m - V_g V_app = 0.4536 cm^3 - 0.06804 cm^3 V_app = 0.38556 cm^3 Send me the next one 📸