This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's the solution for question 3: Given: Initial volume (V_0) = 0.6 m^3 Initial temperature (T_0) = 20 °C Final temperature (T_f) = 70 °C Linear coefficient of expansion of glass (_g) = 11 × 10^-6 /°C Volume coefficient of expansion of mercury (_m) = 20 × 10^-5 /°C Step 1: Calculate the change in temperature ( T). T = T_f - T_0 = 70 °C - 20 °C = 50 °C Step 2: Calculate the volumetric expansion coefficient of glass (_g). The volumetric expansion coefficient for a solid is approximately three times its linear expansion coefficient. _g = 3 _g = 3 × (11 × 10^-6 /°C) = 33 × 10^-6 /°C Step 3: Calculate the change in volume of the glass bulb ( V_g). V_g = V_0 _g T V_g = (0.6 m^3) × (33 × 10^-6 /°C) × (50 °C) V_g = 0.00099 m^3 Step 4: Calculate the change in volume of the mercury ( V_m). V_m = V_0 _m T V_m = (0.6 m^3) × (20 × 10^-5 /°C) × (50 °C) V_m = (0.6 m^3) × (200 × 10^-6 /°C) × (50 °C) V_m = 0.006 m^3 Step 5: Calculate the overflow of mercury. The overflow is the difference between the absolute expansion of mercury and the expansion of the glass bulb. Overflow = V_m - V_g Overflow = 0.006 m^3 - 0.00099 m^3 Overflow = 0.00501 m^3 3 done, 2 left today. You're making progress.