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A machine has a velocity ratio of 8 and operates at an efficiency of 65%. It is used to lift a load of 2600N. a) Mechanical advantage b) Effort required.

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2 parts
a
5.2
b

500 N500 \, \text{N}

Step-by-step solution

4 steps

I will solve the complete problem visible in the image. The first part (c) about the motor's power cannot be solved as crucial information (like force, distance, or work done) is missing from the image.

Problem: Machine Calculations

Given:

  • Velocity Ratio (VR) = 8
  • Efficiency (η\eta) = 65%
  • Load = 2600 N

Part a· 2 steps

Mechanical Advantage (M.A.)

  1. Use the formula relating efficiency, mechanical advantage, and velocity ratio.

    η=M.A.V.R.×100%\eta = \frac{\text{M.A.}}{\text{V.R.}} \times 100\%

  2. Rearrange the formula to solve for M.A.

    and substitute the given values.

    M.A.=η×V.R.100%\text{M.A.} = \frac{\eta \times \text{V.R.}}{100\%} M.A.=65%×8100%\text{M.A.} = \frac{65\% \times 8}{100\%} M.A.=65×8100\text{M.A.} = \frac{65 \times 8}{100} M.A.=520100\text{M.A.} = \frac{520}{100} M.A.=5.2\text{M.A.} = 5.2

    The mechanical advantage is 5.2\boxed{5.2}.

Part b

500 N500 \, \text{N}

Effort required

  1. Use the formula for mechanical advantage.

    M.A.=LoadEffort\text{M.A.} = \frac{\text{Load}}{\text{Effort}}

  2. Rearrange the formula to solve for Effort and substitute the known values (M.A.

    from part a and given Load).

    Effort=LoadM.A.\text{Effort} = \frac{\text{Load}}{\text{M.A.}} Effort=2600 N5.2\text{Effort} = \frac{2600 \, \text{N}}{5.2} Effort=500 N\text{Effort} = 500 \, \text{N}

    The effort required is 500 N\boxed{500 \, \text{N}}.

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