A mass of 2.4 kg is attached to the end of a wire and produces an extension of 0.5mm. Given that the diameter of the wire is 5.6mm, calculate the cross-sectional area of the wire and the tensile stress.

• Mass ($m$) = $2.4 \text{ kg}$
• Extension ($\Delta L$) = $0.5 \text{ mm} = 0.5 \times 10^{-3} \text{ m}$ (This value is not needed for the requested calculations but is noted.)
• Diameter ($d$) = $5.6 \text{ mm} = 5.6 \times 10^{-3} \text{ m}$
• Acceleration due to gravity ($g$) = $9.81 \text{ m/s}^2$ (standard value)

The force ($F$) is due to the weight of the mass attached.

First, find the radius ($r$) from the diameter ($d$).

The cross-sectional area ($A$) of the wire is given by the formula for the area of a circle.

Tensile stress ($\sigma$) is defined as the ratio of the applied force to the cross-sectional area.

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