This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey Eharuner, good to see you again. To calculate the energy stored in the wire, we use the formula for elastic potential energy. Step 1: Identify the given values and the formula. Given: Length of wire, l = 4 m Cross-sectional area, A = 3 × 10^-6 m^2 Extension, e = 1 mm = 1 × 10^-3 m Young's Modulus, E = 2 × 10^11 Pa The energy stored (elastic potential energy) in a stretched wire is given by the formula: U = (1)/(2) (E A e^2)/(l) Step 2: Substitute the given values into the formula. U = (1)/(2) (2 × 10^11 Pa) × (3 × 10^-6 m^2) × (1 × 10^-3 m)^24 m Step 3: Perform the calculation. U = (1)/(2) (2 × 10^11) × (3 × 10^-6) × (1 × 10^-6)4 U = 2 × 3 × 10^11 - 6 - 62 × 4 U = 6 × 10^-18 U = (0.6)/(8) U = 0.075 J The energy stored in the wire is 0.075 J. Comparing this with the given options: A. 0.053J B. 0.15J C. 0.075J D. 0.0075J The correct option is C. The final answer is C. 0.075J Send me the next one 📸