Calculate the initial resistance of the wire. length of wire = 1.0 m, cross sectional area of wire = 2.9 × 10^-8 m2, resistivity of wire = 4.9 × 10^-7 Ω m

Step 1: Recall the formula for resistance. The resistance $R$ of a wire is given by the formula: $R = \frac{\rho L}{A}$ where $\rho$ is the resistivity, $L$ is the length, and $A$ is the cross-sectional area.

Step 2: Substitute the given values into the formula. Given: $L = 1.0 \text{ m}$ $A = 2.9 \times 10^{-8} m^2$ $\rho = 4.9 \times 10^{-7} \Omega \text{ m}$

$R = \frac{(4.9 \times 10^{-7} \Omega m)(1.0 m)}{2.9 \times 10^{-8} m^2}$

Step 3: Calculate the initial resistance. $R = \frac{4.9 \times 10^{-7}}{2.9 \times 10^{-8}} \Omega$ $R = 16.89655... \Omega$ Rounding to three significant figures: $R = 16.9 \Omega$

The initial resistance of the wire is $\boxed{16.9 \Omega}$.

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