This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the problems. 45. Step 1: Identify the given resistivity. The resistivity () of the conductor is given as 1.7 × 10^-8 \, · m. The length and cross-sectional area are not needed to find conductivity. Step 2: Calculate the conductivity. Conductivity () is the reciprocal of resistivity (). = (1)/() = (1)/(1.7 × 10^-8) \, · m = 0.588235 × 10^8 \, S/m ≈ 5.88 × 10^7 \, S/m The conductivity of the conductor is 5.88 × 10^7 \, S/m. 46. Step 1: Calculate the resistivity from the given conductivity. The conductivity () is 3.2 × 10^7 \, S/m. Resistivity () is the reciprocal of conductivity. = (1)/() = (1)/(3.2 × 10^7 \, S/m) = 0.3125 × 10^-7 \, · m = 3.125 × 10^-8 \, · m Step 2: Calculate the resistance using the resistivity, length, and cross-sectional area. The length (L) is 15 \, m and the cross-sectional area (A) is 2 × 10^-6 \, m^2. The formula for resistance is: R = (L)/(A) R = (3.125 × 10^-8 \, · m) × 15 \, m2 × 10^-6 \, m^2 R = 3.125 × 10^-8 × 152 × 10^-6 \, R = 46.875 × 10^-82 × 10^-6 \, R = 23.4375 × 10^-2 \, R = 0.234375 \, Rounding to three significant figures: R ≈ 0.234 \, The resistance of the conductor is 0.234 \, . Send me the next one 📸