Calculate the conductivity of a conductor with resistivity of 1.7 imes 10⁻⁸ Calculate the resistance of a conductor with conductivity of 3.2 imes 107 S/m, length 15 m, and cross-sectional area 2 imes

The resistivity ($\rho$) of the conductor is given as $1.7 \times 10^{-8} \, \Omega \cdot \text{m}$. The length and cross-sectional area are not needed to find conductivity.

Conductivity ($\sigma$) is the reciprocal of resistivity ($\rho$).

The conductivity of the conductor is $\boxed{\text{5.88} \times 10^7 \, \text{S/m}}$.

46.

The conductivity ($\sigma$) is $3.2 \times 10^7 \, \text{S/m}$. Resistivity ($\rho$) is the reciprocal of conductivity.

The length ($L$) is $15 \, \text{m}$ and the cross-sectional area ($A$) is $2 \times 10^{-6} \, \text{m}^2$. The formula for resistance is:

Rounding to three significant figures:

The resistance of the conductor is $\boxed{\text{0.234} \, \Omega}$.