This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Haya Jozee, wacha tutatue swali hili la waya. 1. Tafuta resistivity ya waya. Step 1: Kokotoa upinzani (R) wa waya kwa kutumia Sheria ya Ohm (V = IR). Tunapewa: Potential difference V = 4 V Current I = 0.2 A R = (V)/(I) = 4 V0.2 A R = 20 Step 2: Kokotoa resistivity () ya waya kwa kutumia fomula R = (L)/(A). Tunapewa: Upinzani R = 20 Urefu wa waya L = 3 m Eneo la msalaba A = 9 × 10^-9 m^2 = (R × A)/(L) = 20 × 9 × 10^-9 m^23 m = 180 × 10^-93 · m = 60 × 10^-9 · m = 6.0 × 10^-8 · m Resistivity ya waya ni 6.0 × 10^-8 · m. 2. Conductivity ya waya. Step 3: Kokotoa conductivity () ya waya. Conductivity ni kinyume cha resistivity ( = (1)/()). = (1)/(6.0 × 10^-8) · m = 0.1666... × 10^8 S/m = 1.67 × 10^7 S/m Conductivity ya waya ni 1.67 × 10^7 S/m. That's 2 down. 3 left today — send the next one.