A copper wire is 2 m2m long and has a cross-sectional area of 1×10−6 m2. Given that the resistivity of copper is ρ=1.7×10−8 Ω⋅m. calculate the resistance of the wire.

Question

Asked on June 7, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-06-07T13:07:30.558Z

Step 1: Recall the formula for resistance R in terms of resistivity , length L, and cross-sectional area A. R = (L)/(A) Step 2: Substitute the given values into the formula. Given: L = 2 m A = 1 × 10^-6 m^2 = 1.7 × 10^-8 · m R = (1.7 × 10^-8 · m) 2 m1 × 10^-6 m^2 Step 3: Perform the calculation. R = 1.7 × 10^-8 × 21 × 10^-6 R = 3.4 × 10^-81 × 10^-6 R = 3.4 × 10^-8 - (-6) R = 3.4 × 10^-2 R = 0.034 The resistance of the wire is 0.034 . Send me the next one 📸

Accepted Answer · 2026-06-07T13:07:30.558Z

Step 1: Recall the formula for resistance R in terms of resistivity , length L, and cross-sectional area A. R = (L)/(A) Step 2: Substitute the given values into the formula. Given: L = 2 m A = 1 × 10^-6 m^2 = 1.7 × 10^-8 · m R = (1.7 × 10^-8 · m) 2 m1 × 10^-6 m^2 Step 3: Perform the calculation. R = 1.7 × 10^-8 × 21 × 10^-6 R = 3.4 × 10^-81 × 10^-6 R = 3.4 × 10^-8 - (-6) R = 3.4 × 10^-2 R = 0.034 The resistance of the wire is 0.034 . Send me the next one 📸

A copper wire is 2 m2m long and has a cross-sectional area of 1×10−6 m2. Given that the resistivity of copper is ρ=1.7×10−8 Ω⋅m. calculate the resistance of the wire.

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A copper wire is 2 m2m long and has a cross-sectional area of 1×10−6 m2. Given that the resistivity of copper is ρ=1.7×10−8 Ω⋅m. calculate the resistance of the wire.

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