A rope is used to pull a toy along a horizontal surface. The rope makes an angle of 60 degrees with the horizontal, and the effective force pulling the toy horizontally is 5 N. What is the tension in

The angle of the rope with the horizontal is $\theta = 60^\circ$.
The effective force pulling the toy along the horizontal surface is $F_x = 5 \text{ N}$.
We need to calculate the tension in the rope, $T$.

The horizontal component of the tension in the rope is the effective force pulling the toy along the horizontal surface. This relationship is given by:

We know that $\cos(60^\circ) = \frac{1}{2}$.

To find $T$, multiply both sides by 2:

The tension in the rope is $\text{10 N}$.