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A sphere with initial charge of 8 microcoulombs touches three neutral identical spheres successively. What is the final charge on the initial sphere?

Physics

ScanSolve AI Answer

Answer

A

Step-by-step solution

3 steps

a)

  1. First contact

    The initial sphere has a charge of 8μC8 \mu C. It makes contact with the first neutral sphere (charge 0μC0 \mu C). Since the spheres are identical, the total charge is distributed equally.
    The charge on the initial sphere after the first contact is:

    Q1=8μC+0μC2=4μCQ_{1} = \frac{8 \mu C + 0 \mu C}{2} = 4 \mu C
  2. Second contact

    The initial sphere (now with 4μC4 \mu C) makes contact with the second neutral sphere (charge 0μC0 \mu C).
    The charge on the initial sphere after the second contact is:

    Q2=4μC+0μC2=2μCQ_{2} = \frac{4 \mu C + 0 \mu C}{2} = 2 \mu C
  3. Third contact

    The initial sphere (now with 2μC2 \mu C) makes contact with the third neutral sphere (charge 0μC0 \mu C).
    The charge on the initial sphere after the third contact is:

    Q3=2μC+0μC2=1μCQ_{3} = \frac{2 \mu C + 0 \mu C}{2} = 1 \mu C

    The final charge on the initial sphere is 1μC1 \mu C.

    The correct option is a).

    The final answer is 1 \muC\boxed{\text{1 \mu C}}.

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