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A steel bolt and a brass bolt are placed side-by-side with a 5.0 μm gap between them at 28.70°C. If the temperature increases, how much must the temperature increase for the bolts to touch? The coeffi

Physics

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To solve this problem, the initial lengths of the steel and brass bolts are required. The problem statement provides the initial gap, the initial temperature, and the coefficients of linear expansion for steel and brass, but it does not provide the initial lengths (L0,steelL_{0, \text{steel}} and L0,brassL_{0, \text{brass}}) of the bolts themselves.

Here's why this information is needed:

  1. Identify the given values.

    Initial gap, gap=5.0 μm=5.0×10−6 m\text{gap} = 5.0 \, \mu\text{m} = 5.0 \times 10^{-6} \, \text{m}
    Initial temperature, T0=28.70∘CT_0 = 28.70^\circ\text{C}
    Coefficient of linear expansion for steel, αsteel=11×10−6 (∘C)−1\alpha_{\text{steel}} = 11 \times 10^{-6} \, (^\circ\text{C})^{-1}
    Coefficient of linear expansion for brass, αbrass=19×10−6 (∘C)−1\alpha_{\text{brass}} = 19 \times 10^{-6} \, (^\circ\text{C})^{-1}

  2. Formulate the expansion equations.

    The change in length for each bolt is given by the linear thermal expansion formula:

    ΔL=L0αΔT\Delta L = L_0 \alpha \Delta T

    For the steel bolt:

    ΔLsteel=L0,steelαsteelΔT\Delta L_{\text{steel}} = L_{0, \text{steel}} \alpha_{\text{steel}} \Delta T

    For the brass bolt:

    ΔLbrass=L0,brassαbrassΔT\Delta L_{\text{brass}} = L_{0, \text{brass}} \alpha_{\text{brass}} \Delta T

    where ΔT=Tf−T0\Delta T = T_f - T_0 is the change in temperature.

  3. Set up the condition for the bolts to touch.

    The bolts will touch when the sum of their expansions equals the initial gap:

    ΔLsteel+ΔLbrass=gap\Delta L_{\text{steel}} + \Delta L_{\text{brass}} = \text{gap}

    Substituting the expansion formulas:

    L0,steelαsteelΔT+L0,brassαbrassΔT=gapL_{0, \text{steel}} \alpha_{\text{steel}} \Delta T + L_{0, \text{brass}} \alpha_{\text{brass}} \Delta T = \text{gap}

    Factoring out ΔT\Delta T:

    (L0,steelαsteel+L0,brassαbrass)ΔT=gap(L_{0, \text{steel}} \alpha_{\text{steel}} + L_{0, \text{brass}} \alpha_{\text{brass}}) \Delta T = \text{gap}

    Solving for ΔT\Delta T:

    ΔT=gapL0,steelαsteel+L0,brassαbrass\Delta T = \frac{\text{gap}}{L_{0, \text{steel}} \alpha_{\text{steel}} + L_{0, \text{brass}} \alpha_{\text{brass}}}
  4. Determine the final temperature.

    The final temperature TfT_f would be:

    Tf=T0+ΔTT_f = T_0 + \Delta T

    a) At what temperature will the bolts touch?
    As shown in Step 3, to calculate a numerical value for ΔT\Delta T and thus TfT_f, the initial lengths of the steel bolt (L0,steelL_{0, \text{steel}}) and the brass bolt (L0,brassL_{0, \text{brass}}) are required. Since these values are not provided in the problem statement, a numerical answer cannot be determined.

    b) determine respectively, the change in the length of the steel and the brass at that temperature.
    Similarly, without the initial lengths (L0,steelL_{0, \text{steel}} and L0,brassL_{0, \text{brass}}) and the calculated ΔT\Delta T, the individual changes in length (ΔLsteel\Delta L_{\text{steel}} and ΔLbrass\Delta L_{\text{brass}}) cannot be determined numerically.

    Please provide the initial lengths of the bolts if you would like a numerical solution.

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