We read your photo as:

An electric field of magnitude E is produced at the center of a uniformly charged ring by one half of the ring. What is the magnitude of the total electric field at the center of the ring?

Physics

ScanSolve AI Answer

Step 1: Analyze Question 1.
The electric field at the center of a uniformly charged ring is zero. This means the vector sum of the electric fields due to all parts of the ring at the center is zero.
Let E⃗AKB\vec{E}_{AKB} be the electric field at OO due to the part AKBAKB, and E⃗ACDB\vec{E}_{ACDB} be the electric field at OO due to the part ACDBACDB.
We are given that E⃗AKB\vec{E}_{AKB} has magnitude EE and is directed along KOKO.
The total electric field at OO is E⃗total=E⃗AKB+E⃗ACDB=0\vec{E}_{total} = \vec{E}_{AKB} + \vec{E}_{ACDB} = 0.
Therefore,

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp