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An orange of mass 1.2 kg has a velocity of 10 m/s. Calculate its kinetic energy.

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2 parts
1

60 J\text{60 J}

2

9.13 m/s\text{9.13 m/s}

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Part 1· 3 steps

An orange of mass 1.2 kg has a velocity of 10 m/s. Calculate its kinetic energy.

  1. Identify the given values.

    Mass, m=1.2 kgm = 1.2 \text{ kg}
    Velocity, v=10 m/sv = 10 \text{ m/s}

  2. Use the formula for kinetic energy.

    The formula for kinetic energy (KEKE) is:

    KE=12mv2KE = \frac{1}{2}mv^2

  3. Substitute the values into the formula and calculate.

    KE=12×(1.2 kg)×(10 m/s)2KE = \frac{1}{2} \times (1.2 \text{ kg}) \times (10 \text{ m/s})^2 KE=12×1.2 kg×100 m2/s2KE = \frac{1}{2} \times 1.2 \text{ kg} \times 100 \text{ m}^2/\text{s}^2 KE=0.6 kg×100 m2/s2KE = 0.6 \text{ kg} \times 100 \text{ m}^2/\text{s}^2 KE=60 JKE = 60 \text{ J}

    The kinetic energy of the orange is 60 J\boxed{\text{60 J}}.

Part 2

9.13 m/s\text{9.13 m/s}

If a piece of stone has a kinetic energy of 50 J and a mass of 1.2 kg, find its velocity.

  1. Identify the given values.

    Kinetic Energy, KE=50 JKE = 50 \text{ J}
    Mass, m=1.2 kgm = 1.2 \text{ kg}

  2. Use the formula for kinetic energy and rearrange it to solve for velocity.

    The formula for kinetic energy (KEKE) is:

    KE=12mv2KE = \frac{1}{2}mv^2

    To find velocity (vv), rearrange the formula:

    2KE=mv22KE = mv^2 v2=2KEmv^2 = \frac{2KE}{m} v=2KEmv = \sqrt{\frac{2KE}{m}}

  3. Substitute the values into the rearranged formula and calculate.

    v=2×50 J1.2 kgv = \sqrt{\frac{2 \times 50 \text{ J}}{1.2 \text{ kg}}} v=100 J1.2 kgv = \sqrt{\frac{100 \text{ J}}{1.2 \text{ kg}}} v=83.333... m2/s2v = \sqrt{83.333... \text{ m}^2/\text{s}^2} v≈9.1287 m/sv \approx 9.1287 \text{ m/s}

    The velocity of the stone is approximately 9.13 m/s\boxed{\text{9.13 m/s}}.

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