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Calculate capacitive reactance, inductive reactance, and resonance frequency given specific circuit parameters.

Physics

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Step-by-step solution

5 steps

Here are the solutions to the problems:

1) Capacitive Reactance

  1. Identify the given values and the formula for capacitive reactance.

    Given: Capacitance C=10 mF=10×10−3 FC = 10 \text{ mF} = 10 \times 10^{-3} \text{ F}, Frequency f=60 Hzf = 60 \text{ Hz}.
    The formula for capacitive reactance (XCX_C) is:

    XC=12πfCX_C = \frac{1}{2\pi f C}
  2. Substitute the values and calculate XCX_C.

    XC=12π(60 Hz)(10×10−3 F)X_C = \frac{1}{2\pi (60 \text{ Hz}) (10 \times 10^{-3} \text{ F})} XC=11.2πΩX_C = \frac{1}{1.2\pi} \Omega XC≈13.7699ΩX_C \approx \frac{1}{3.7699} \Omega XC≈0.265ΩX_C \approx \boxed{0.265 \Omega}

    2) Inductive Reactance

  3. Identify the given values and the formula for inductive reactance.

    Given: Inductance L=2 HL = 2 \text{ H}, Frequency f=60 Hzf = 60 \text{ Hz}.
    The formula for inductive reactance (XLX_L) is:

    XL=2πfLX_L = 2\pi f L
  4. Substitute the values and calculate XLX_L.

    XL=2π(60 Hz)(2 H)X_L = 2\pi (60 \text{ Hz}) (2 \text{ H}) XL=240πΩX_L = 240\pi \Omega XL≈753.98ΩX_L \approx \boxed{753.98 \Omega}

    3) Resonance Frequency

  5. Identify the given values and the formula for resonance frequency.

    Given: Inductance $L = 200 mH = 200 \times

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