Dimension of acceleration

Physics

ScanSolve AI Answer

Answer

[L][T−2][L][T^{-2}]

Step-by-step solution

5 steps
  1. Define acceleration.

    Acceleration is the rate of change of velocity.

    a=ΔvΔta = \frac{\Delta v}{\Delta t}
  2. Define velocity.

    Velocity is the rate of change of displacement (or distance).

    v=ΔdΔtv = \frac{\Delta d}{\Delta t}
  3. Substitute the definition of velocity into the acceleration formula.

    a=(ΔdΔt)Δt=Δd(Δt)2a = \frac{\left(\frac{\Delta d}{\Delta t}\right)}{\Delta t} = \frac{\Delta d}{(\Delta t)^2}
  4. Determine the fundamental dimensions for displacement and time.

    The dimension of displacement (Δd\Delta d) is length, denoted by [L][L].
    The dimension of time (Δt\Delta t) is time, denoted by [T][T].

  5. Substitute the fundamental dimensions into the acceleration formula.

    Dimension of acceleration = [L][T]2=[L][T−2]\frac{[L]}{[T]^2} = [L][T^{-2}]

    Thus, the dimension of acceleration is [L][T−2][L][T^{-2}].

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