This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the questions: QUESTION ONE b) Calculate the energy a parallel plate capacitor (charged to a voltage of V=12V) with the following: Plate area A = 2m^2* Plate separation d = 0.02m* Vacuum permittivity _0 = 8.854 × 10^-12 F/m* Step 1: Calculate the capacitance C of the parallel plate capacitor. The formula for the capacitance of a parallel plate capacitor in vacuum is: C = (_0 A)/(d) Substitute the given values: C = (8.854 × 10^-12 F/m) × (2 m^2)0.02 m C = 17.708 × 10^-120.02 F C = 885.4 × 10^-12 F C = 885.4 pF Step 2: Calculate the energy W_e stored in the capacitor. The formula for the energy stored in a capacitor is: W_e = (1)/(2) C V^2 Substitute the calculated capacitance C and the given voltage V: W_e = (1)/(2) × (885.4 × 10^-12 F) × (12 V)^2 W_e = (1)/(2) × (885.4 × 10^-12) × 144 J W_e = 442.7 × 10^-12 × 144 J W_e = 63748.8 × 10^-12 J