This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
You're on a roll — here are the solutions to questions Q.1 to Q.18 from Section A. Section A Q.1: Step 1: Use the formula for electric field intensity between parallel plates: E = (V)/(d) where V is the potential difference and d is the separation. Step 2: Substitute the given values V = 12 V and d = 3 cm = 0.03 m. E = 12 V0.03 m E = 400 V/m or 400 N/C The correct option is 400 N/C. Q.2: The electric flux through a closed surface, according to Gauss's Law (_E = Q_enc_0), depends only on the net charge enclosed by the surface and the permittivity of the medium. It does not depend on the shape or size of the surface. The correct option is Shape and size of the surface. Q.3: When a dielectric material is inserted between the plates of a charged capacitor, it becomes polarized. This polarization creates an induced electric field within the dielectric that opposes the original electric field, thereby reducing the net electric field in the region between the plates. The correct option is Decreases. Q.4: Step 1: The resistance of a wire is given by R = (L)/(A), where is resistivity, L is length, and A is cross-sectional area. The volume V = AL. Step 2: If the length L is doubled to 2L while the volume V remains constant, the new area A' must be A' = V/(2L) = (AL)/(2L) = A/2. Step 3: Calculate the new resistance R'. R' = (2L)/(A/2) = (4L)/(A) = 4R The resistance is quadrupled. The correct option is is quadrupled. Q.5: A thermocouple generates a voltage when there is a temperature difference between two dissimilar electrical conductors. This phenomenon is known as the Seebeck effect. The correct option is Seebeck effect. Q.6: Step 1: Use the formula for the magnetic force on a current-carrying wire: F = I L B where I is current, L is length, B is magnetic field strength, and is the angle between the current direction and the magnetic field. Step 2: Substitute the given values: I = 5 A, L = 100 cm = 1 m, B = 4 T, = 45^. F = (5 A) (1 m) (4 T) (45^) F = 20 × (1)/(sqrt(2)) N F = (20)/(sqrt(2)) N = 10sqrt(2) N ≈ 14.14 N The correct option is 14.14 N. Q.7: The iron core in a transformer is laminated (made of thin, insulated sheets) to increase the electrical resistance to eddy currents. This significantly reduces the magnitude of these circulating currents, thereby minimizing the energy loss as heat due to the heating effect of eddy currents. The correct option is Reduce heating effect of eddy currents. Q.8: In an RLC series AC circuit, resonance occurs when the inductive reactance (X_L) equals the capacitive reactance (X_C). The impedance Z is given by Z = sqrt(R^2 + (X_L - X_C)^2). At resonance, X_L - X_C = 0, so the impedance becomes $Z =