This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

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\rho h g$:
Here are the solutions for questions 3b and 5a:
b) Derivation of : Step 1: Pressure is defined as force per unit area. Step 2: The force exerted by the liquid column is its weight, which is . Step 3: The mass of the liquid can be expressed using its density and volume , so . Step 4: The volume of a liquid column with cross-sectional area and height is . Step 5: Cancel out the area from the numerator and denominator.
a) Explain why height h is less than 20 cm: At the same horizontal level in the U-tube (the interface between liquids X and Y), the pressure exerted by both liquid columns must be equal. The pressure exerted by a liquid column is given by . Since liquid X has a density of and liquid Y has a density of , liquid X is denser than liquid Y. For the pressures to balance (), the height of the denser liquid X () must be less than the height of the less dense liquid Y ().
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3. b) Derivation of P = h g: Step 1: Pressure is defined as force per unit area.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.