What happens to the PE if the stone falls to the ground

Physics

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Answer

The PE becomes 0 J

Step-by-step solution

4 steps
  1. Gravitational potential energy (PE) is defined as

    PE=mghPE = m g h

    where mm is mass in kg, g≈9.8g \approx 9.8 m/s² is acceleration due to gravity, and hh is height above the ground in m. Units of PE are joules (J).

  2. Before falling, assume the stone is at height hh above ground.

    Initial PE:

    PEi=mgh(J)PE_i = m g h \quad \text{(J)}
  3. When the stone falls to the ground, h=0h = 0 m.

    Final PE:

    PEf=mg×0=0JPE_f = m g \times 0 = 0 \quad \text{J}
  4. Change in PE

    ΔPE=PEf−PEi=0−mgh=−mghJ\Delta PE = PE_f - PE_i = 0 - m g h = -m g h \quad \text{J}

    The PE decreases to 0 J (taking ground level as the zero reference point).
    The PE becomes 0 J

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