State I. the two characteristics of oscillatory motion. II. two examples of bodies exhibiting oscillatory motion. A body of mass 0.5 kg is suspended vertically on a spiral spring. If the extension produced is 0.2 m, calculate the force constant of the spring.

b)i) I. The two characteristics of oscillatory motion are: • It is a periodic motion, meaning it repeats itself after a fixed interval of time. • It is a to-and-fro motion about a fixed equilibrium position. II. Two examples of bodies exhibiting oscillatory motion are: • A simple pendulum swinging. • A mass suspended from a spring oscillating vertically. b)ii) Step 1: Calculate the force (weight) exerted by the mass on the spring. The force F is equal to the weight of the mass, which is given by F = mg. F = 0.5\, kg × 10\, m/s^2 F = 5\, N Step 2: Use Hooke's Law to calculate the force constant of the spring. Hooke's Law states F = kx, where F is the force, k is the force constant, and x is the extension. Rearranging for k: k = (F)/(x) Substitute the values: k = 5\, N0.2\, m k = 25\, N/m The force constant of the spring is: 25\, N/m Drop the next question.