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Identify the circuit configuration when K is closed.

Physics

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3. (c)

  1. Identify the circuit configuration when K is closed.

    When key K is closed, it creates a short circuit across the 4 Ω4\,\Omega resistor (R2) that is in parallel with it. This means current will flow through the closed key K, effectively bypassing R2. The resistance of this parallel combination becomes 0 Ω0\,\Omega.
    The circuit then consists of the first 4 Ω4\,\Omega resistor (R1) in series with the 2 Ω2\,\Omega resistor (R3).

  2. Calculate the total resistance of the circuit.

    Rtotal=R1+R3R_{total} = R1 + R3 Rtotal=4 Ω+2 ΩR_{total} = 4\,\Omega + 2\,\Omega Rtotal=6 ΩR_{total} = 6\,\Omega

    The combined resistance of the circuit when the key, K is closed is 6 Ω\boxed{\text{6 }\Omega}.

    3. (d)

  3. Identify the total voltage and total resistance.

    Total voltage, V=12 VV = 12\,\text{V}
    Total resistance, Rtotal=6 ΩR_{total} = 6\,\Omega (from part 3. (c))

  4. Calculate the ammeter reading (total current).

    Using Ohm's Law, I=VRtotalI = \frac{V}{R_{total}}.

    I=12 V6 ΩI = \frac{12\,\text{V}}{6\,\Omega} I=2.0 AI = 2.0\,\text{A}

    The ammeter reading when the key, K is closed is 2.0 A\boxed{\text{2.0 A}}.

    3. (e)

    i)

  5. State the equivalence of 1 KWh in joules.

    1 KWh=1000 W×1 hour1\,\text{KWh} = 1000\,\text{W} \times 1\,\text{hour} 1 KWh=1000 J/s×(60×60) s1\,\text{KWh} = 1000\,\text{J/s} \times (60 \times 60)\,\text{s} 1 KWh=1000 J/s×3600 s1\,\text{KWh} = 1000\,\text{J/s} \times 3600\,\text{s} 1 KWh=3,600,000 J1\,\text{KWh} = 3,600,000\,\text{J} 1 KWh=3.6×106 J1\,\text{KWh} = 3.6 \times 10^6\,\text{J}

    The equivalence of 1 KWh in joules is 3.6×106 J\boxed{3.6 \times 10^6\,\text{J}}.

    ii)

  6. Calculate the total power consumption.

    Power of electric cooker = 1000 W1000\,\text{W}
    Power of immersion heater = 3000 W3000\,\text{W}
    Total power, Ptotal=1000 W+3000 W=4000 WP_{total} = 1000\,\text{W} + 3000\,\text{W} = 4000\,\text{W}

  7. Convert total power to kilowatts.

    Ptotal=4000 W=4 kWP_{total} = 4000\,\text{W} = 4\,\text{kW}
  8. Calculate the total energy consumed in KWh.

    Time, t=10 hourst = 10\,\text{hours}
    Energy consumed, E=Ptotal×tE = P_{total} \times t

    E=4 kW×10 hoursE = 4\,\text{kW} \times 10\,\text{hours} E=40 KWhE = 40\,\text{KWh}
  9. Calculate the cost of electricity.

    Cost per KWh = 75 frs75\,\text{frs}
    Total cost = Energy consumed ×\times Cost per KWh

    Total cost=40 KWh×75 frs/KWh\text{Total cost} = 40\,\text{KWh} \times 75\,\text{frs/KWh} Total cost=3000 frs\text{Total cost} = 3000\,\text{frs}

    The cost of electricity used is 3000 frs\boxed{\text{3000 frs}}.

    4. (a)

    i)
    Two properties of plastics that make them useful as engineering materials are:

    • Lightweight: Plastics have a low density, making them suitable for applications where weight reduction is crucial, such as in aerospace and automotive industries.
    • Corrosion resistance: Many plastics are highly resistant to chemical corrosion, making them ideal for pipes, containers, and components exposed to harsh environments.

    ii)

    • Thermoplastics: These plastics can be repeatedly softened by heating and hardened by cooling. Their polymer chains are held together by weak intermolecular forces, allowing them to be reshaped multiple times. Examples include polyethylene and PVC.
    • Thermosetting plastics: These plastics undergo an irreversible chemical change when heated, forming a rigid, cross-linked structure. Once set, they cannot be softened or reshaped by further heating without degrading. Examples include epoxy resins and bakelite.

    iii)
    Thermoplastics can be recycled because their polymer chains are linear or branched and held together by relatively weak intermolecular forces. When heated, these forces weaken, allowing the material to melt and be reshaped without significant chemical degradation. Thermosetting plastics, however, form strong, permanent covalent cross-links between their polymer chains during curing. This rigid, three-dimensional network prevents them from melting or being reshaped upon heating; instead, they char or burn, making them difficult to recycle.

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