If a solid has 4 × 10²⁰ atoms per kilogram of mass, and one electron is removed from each atom, what will be the charge obtained by 1 gram of the solid?

Step 1: Number of atoms in 1 kg of dry human hair, N = 4 × 10²⁰. Step 2: Charge of one electron, e = 1.6 × 10⁻¹⁹ C. Step 3: Total charge released, Q = N × e. Substitute the values: Q = (4 × 10²⁰) × (1.6 × 10⁻¹⁹) C Multiply the coefficients and add the powers of 10: Q = (4 × 1.6) × 10²⁰⁺⁽⁻¹⁹⁾ C = 6.4 × 10¹ C Simplify: Q = 64 C The correct option is (b). 64 C

If a solid has 4 × 10²⁰ atoms per kilogram of mass, and one electron is removed from each atom, what will be the charge obtained by 1 gram of the solid?

Step 1: Number of atoms in 1 kg of dry human hair, N = 4 × 10²⁰. Step 2: Charge of one electron, e = 1.6 × 10⁻¹⁹ C. Step 3: Total charge released, Q = N × e. Substitute the values: Q = (4 × 10²⁰) × (1.6 × 10⁻¹⁹) C Multiply the coefficients and add the powers of 10: Q = (4 × 1.6) × 10²⁰⁺⁽⁻¹⁹⁾ C = 6.4 × 10¹ C Simplify: Q = 64 C The correct option is (b). 64 C

Solved: If a solid has 4 × 10²⁰ atoms per kilogram of mass…

Number of atoms in 1 kg of dry human hair, $N = 4 \times 10^{20}$ .
Charge of one electron, $e = 1.6 \times 10^{-19} \, \mathrm{C}$ .
Total charge released, $Q = N \times e$ .
Substitute the values:
$Q = (4 \times 10^{20}) \times (1.6 \times 10^{-19}) \, \mathrm{C}$
Multiply the coefficients and add the powers of 10:
$Q = (4 \times 1.6) \times 10^{20 + (-19)} \, \mathrm{C} = 6.4 \times 10^{1} \, \mathrm{C}$
Simplify:
$Q = 64 \, \mathrm{C}$
The correct option is (b).

64 C

If a solid has 4 × 10²⁰ atoms per kilogram of mass, and one electron is removed from each atom, what will be the charge obtained by 1 gram of the solid?

Answer

Step-by-step solution

Number of atoms in 1 kg of dry human hair, $N = 4 \times 10^{20}$ .

Charge of one electron, $e = 1.6 \times 10^{-19} \, \mathrm{C}$ .

Total charge released, $Q = N \times e$ .

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If a solid has 4 × 10²⁰ atoms per kilogram of mass, and one electron is removed from each atom, what will be the charge obtained by 1 gram of the solid?

Answer

Step-by-step solution

Number of atoms in 1 kg of dry human hair, N=4×1020N = 4 \times 10^{20}N=4×1020.

Charge of one electron, e=1.6×10−19 Ce = 1.6 \times 10^{-19} \, \mathrm{C}e=1.6×10−19C.

Total charge released, Q=N×eQ = N \times eQ=N×e.

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More Physics Questions

Number of atoms in 1 kg of dry human hair, $N = 4 \times 10^{20}$ .

Charge of one electron, $e = 1.6 \times 10^{-19} \, \mathrm{C}$ .

Total charge released, $Q = N \times e$ .