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Part a) Explain functional equations in chemical kinetics. Part b) A particle's air velocity increases from 10 m/s to 20 m/s in 4 minutes. Calculate its acceleration.

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Here are the solutions to questions 1 and 2.

Part 1

a) Functional equations are mathematical equations that define a function implicitly by relating its values at different points. In chemical kinetics, they are beneficial for modeling how reaction rates depend on concentrations and time, allowing for the prediction of reaction progress. They are applied to derive integrated rate laws, which describe how reactant concentrations change over time for different reaction orders.

Part b· 2 steps

A particle is moving through a magnetic field. After some time, the air velocity has increased from 10 m/s10 \text{ m/s} to 20 m/s20 \text{ m/s} in 4 minutes4 \text{ minutes}. Find the acceleration of the particle.

  1. Convert the time from minutes to seconds.

    t=4 minutes×60 s/minute=240 st = 4 \text{ minutes} \times 60 \text{ s/minute} = 240 \text{ s}

  2. Use the formula for acceleration.

    a=v−uta = \frac{v - u}{t}

    Substitute the given values: initial velocity u=10 m/su = 10 \text{ m/s}, final velocity v=20 m/sv = 20 \text{ m/s}, and time t=240 st = 240 \text{ s}.

    a=20 m/s−10 m/s240 sa = \frac{20 \text{ m/s} - 10 \text{ m/s}}{240 \text{ s}}

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