Calculate the PD in the 2 ohm resistor

August 12, 2026Physics

ScanSolve AI Answer

August 12, 2026

Answer

12 V

Step 1: Identify the current flowing through the 2 ohm resistor. The ammeter indicates that the total current flowing from the source is $6 \text{ A}$ . The $3 \Omega$ resistor, the $2 \Omega$ resistor, and the parallel combination of the $5 \Omega$ and $10 \Omega$ resistors are all connected in series. Therefore, the total current flows through the $2 \Omega$ resistor. $I_{2\Omega} = 6 \text{ A}$

Step 2: Calculate the potential difference (PD) across the 2 ohm resistor using Ohm's Law. Ohm's Law states that $V = IR$ , where $V$ is the potential difference, $I$ is the current, and $R$ is the resistance. $V_{2\Omega} = I_{2\Omega} \times R_{2\Omega}$ $V_{2\Omega} = 6 A \times 2 \Omega$ $V_{2\Omega} = 12 \text{ V}$

The potential difference across the 2 ohm resistor is $\boxed{*12 V*}$ .

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Identify the current flowing through the 2 ohm resistor. The ammeter indicates that the total current flowing from the source is 6 A.

Asked on August 12, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on August 12, 2026

Step 1: Identify the current flowing through the 2 ohm resistor. The ammeter indicates that the total current flowing from the source is 6 A. The 3 resistor, the 2 resistor, and the parallel combination of the 5 and 10 resistors are all connected in series. Therefore, the total current flows through the 2 resistor. I_2 = 6 A Step 2: Calculate the potential difference (PD) across the 2 ohm resistor using Ohm's Law. Ohm's Law states that V = IR, where V is the potential difference, I is the current, and R is the resistance. V_2 = I_2 × R_2 V_2 = 6 A × 2 V_2 = 12 V The potential difference across the 2 ohm resistor is 12 V. Send me the next one 📸