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Calculate the power dissipated by the resistor. A mobile phone charger supplies a current of 1.5 A for 20 minutes. Calculate the total charge transferred.

Physics

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Answer

200 W\text{200 W}

1800 C\text{1800 C}

Step-by-step solution

7 steps

3.

  1. Identify the given values for resistance and voltage.

    We are given the resistance R=50 ΩR = 50 \ \Omega and the voltage V=100 VV = 100 \text{ V}.

  2. Use the formula for power dissipated by a resistor.

    The power PP dissipated by a resistor can be calculated using the formula P=V2RP = \frac{V^2}{R}.

  3. Substitute the values and calculate the power.

    P=(100 V)250 ΩP = \frac{(100 \text{ V})^2}{50 \ \Omega} P=10000 V250 ΩP = \frac{10000 \text{ V}^2}{50 \ \Omega} P=200 WP = 200 \text{ W}

    The power dissipated by the resistor is 200 W\boxed{\text{200 W}}.

    4.

  4. Identify the given values for current and time.

    We are given the current I=1.5 AI = 1.5 \text{ A} and the time t=20 minutest = 20 \text{ minutes}.

  5. Convert the time from minutes to seconds.

    t=20 minutes×60secondsminutet = 20 \text{ minutes} \times 60 \frac{\text{seconds}}{\text{minute}} t=1200 st = 1200 \text{ s}

  6. Use the formula for total charge transferred.

    The total charge QQ transferred is calculated using the formula Q=I×tQ = I \times t.

  7. Substitute the values and calculate the charge.

    Q=1.5 A×1200 sQ = 1.5 \text{ A} \times 1200 \text{ s} Q=1800 CQ = 1800 \text{ C}

    The total charge transferred is 1800 C\boxed{\text{1800 C}}.

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