This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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You're on a roll — here are the solutions to the questions: 5.1 The principle of conservation of linear momentum states that the total linear momentum of an isolated system remains constant. This means the total momentum before an interaction (like a collision or explosion) is equal to the total momentum after the interaction. 5.2 To achieve the maximum decrease in his velocity, Hendrik should throw the iron bar forward, in the direction he is already moving. This action will cause him to recoil backwards relative to the bar, thus decreasing his forward momentum. Forward (in the direction of his motion) 5.3 Step 1: Identify the given values and define the system. Let the direction Hendrik is moving be positive. Mass of Hendrik: m_H = 65 kg Mass of iron bar: m_bar = 5 kg Initial velocity of Hendrik and bar combined: u = 1 m · s^-1 (forward) Total initial mass: M = m_H + m_bar = 65 kg + 5 kg = 70 kg To get the maximum decrease in his velocity, Hendrik throws the bar forward. The speed at which he throws the bar away from himself is 4 m · s^-1. This is the velocity of the bar relative to Hendrik. Let Hendrik's final velocity be v_H. The velocity of the bar relative to the ground, v_bar, is v_H + 4 m · s^-1. Step 2: Apply the principle of conservation of linear momentum. The total momentum before throwing the bar equals the total momentum after throwing the bar. M u = m_H v_H + m_bar v_bar (70 kg)(1 m · s^-1) = (65 kg) v_H + (5 kg) (v_H + 4 m · s^-1) 70 = 65 v_H + 5 v_H + 20 70 = 70 v_H + 20 Step 3: Calculate Hendrik's final velocity. 70 v_H = 70 - 20 70 v_H = 50 v_H = (50)/(70) m · s^-1 v_H = (5)/(7) m · s^-1 v_H ≈ 0.71 m · s^-1 Since v_H is positive, Hendrik's final velocity is in the forward direction (the original direction of motion). 0.71 m·s^-1 forward Got more? Send 'em.