This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Question 25: Step 1: Recall the formula for relative density. Relative density is defined as the ratio of the density of a substance to the density of a reference substance (usually water). Relative density = Density of alloyDensity of water Step 2: Substitute the given values into the formula. We are given the relative density of the alloy as 6.5 and the density of water as 1 g/cm^3. 6.5 = Density of alloy1 g/cm^3 Step 3: Solve for the density of the alloy. Density of alloy = 6.5 × 1 g/cm^3 Density of alloy = 6.5 g/cm^3 Step 4: Compare with the given options. The calculated density matches option (b). The final answer is b) 6.5 g/cm^3. Question 26: Step 1: Determine the dimensions of each term in the equation v^2 = u^2 + 2as. • The dimension of velocity (v or u) is [L T^-1]. Therefore, the dimension of v^2 or u^2 is [L T^-1]^2 = [L^2 T^-2]. • The dimension of acceleration (a) is [L T^-2]. • The dimension of displacement (s) is [L]. • The number 2 is a dimensionless constant. Step 2: Calculate the dimensions of each term in the equation. • Dimension of v^2: [L^2 T^-2] • Dimension of u^2: [L^2 T^-2] • Dimension of 2as: [L T^-2] × [L] = [L^2 T^-2] Step 3: Compare the dimensions of all terms. All terms in the equation (v^2, u^2, and 2as) have the same dimension, which is [L^2 T^-2]. Step 4: Conclude based on dimensional analysis. Since the dimensions of all terms on both sides of the equation are the same, the equation is dimensionally valid. The final answer is b) valid. Send me the next one 📸