This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the answers to Question Five: A. Define the following terms or words i) Displacement is a vector quantity that represents the shortest distance and direction from an object's initial position to its final position. ii) Velocity is a vector quantity that describes the rate at which an object changes its position, including both its speed and direction. iii) Speed is a scalar quantity that describes how fast an object is moving, defined as the magnitude of its velocity or the rate at which it covers distance. iv) Acceleration is a vector quantity that describes the rate at which an object's velocity changes over time, including changes in speed or direction. v) Time is a fundamental scalar quantity that measures the duration of events and the interval between them, representing the progression from past to present to future. B. Prove if the following equation is dimensionally correct The equation is V = U + at. To prove dimensional correctness, we must show that the dimensions of each term in the equation are the same. Step 1: Identify the dimensions of each variable. • Dimension of velocity (V or U): [L][T]^-1 (Length per unit Time) • Dimension of acceleration (a): [L][T]^-2 (Length per unit Time squared) • Dimension of time (t): [T] (Time) Step 2: Determine the dimension of the left-hand side (LHS). The LHS is V. [LHS] = [V] = [L][T]^-1 Step 3: Determine the dimension of the first term on the right-hand side (RHS). The first term on the RHS is U. [U] = [L][T]^-1 Step 4: Determine the dimension of the second term on the right-hand side (RHS). The second term on the RHS is at. [at] = [a] × [t] Substitute the dimensions of a and t: [at] = ([L][T]^-2) × ([T]) [at] = [L][T]^-2+1 [at] = [L][T]^-1 Step 5: Compare the dimensions of all terms. For the equation to be dimensionally correct, the dimensions of all terms added or subtracted must be identical, and equal to the dimension of the term on the other side of the equation. [LHS] = [V] = [L][T]^-1 [U] = [L][T]^-1 [at] = [L][T]^-1 Since all terms have the same dimension, [L][T]^-1, the equation is dimensionally correct. The equation V = U + at is dimensionally correct. Drop the next question.