t = (75.94 − 69.84) / 69.84 * 1 / 0.00358 °C

$$t = \frac{6.10}{69.84} \times \frac{1}{0.00358} \text{ }^\circ\text{C}$$ $$t \approx 0.0873425 \times \frac{1}{0.00358} \text{ }^\circ\text{C}$$

$$t \approx 0.0873425 \times 279.32966 \text{ }^\circ\text{C}$$ $$t \approx 24.390 \text{ }^\circ\text{C}$$

Rounding to a reasonable number of significant figures (e.g., three, based on 0.00358), we get:

$$t \approx 24.4 \text{ }^\circ\text{C}$$

The value of $t$ is $\boxed{24.4 \text{ }^\circ\text{C}}$.