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The decay constant for a certain element is 1.7x10⁻⁹ s⁻¹. Calculate the half-life of the element.

Physics

ScanSolve AI Answer

Answer

40765 s or 11.32 hr\text{40765 s or 11.32 hr}

Step-by-step solution

4 steps
  1. Identify the given decay constant.

    The decay constant (λ\lambda) for the element is given as 1.7×10−5 s−11.7 \times 10^{-5} \text{ s}^{-1}.

  2. Recall the formula for the half-life of a first-order reaction.

    For a first-order decay process, the half-life (t1/2t_{1/2}) is related to the decay constant (λ\lambda) by the formula:

    t1/2=ln⁡(2)λt_{1/2} = \frac{\ln(2)}{\lambda}
  3. Substitute the given value into the formula and calculate.

    t1/2=ln⁡(2)1.7×10−5 s−1t_{1/2} = \frac{\ln(2)}{1.7 \times 10^{-5} \text{ s}^{-1}} t1/2=0.6931.7×10−5 s−1t_{1/2} = \frac{0.693}{1.7 \times 10^{-5} \text{ s}^{-1}} t1/2=40764.70588 st_{1/2} = 40764.70588 \text{ s}
  4. Convert the half-life to a more convenient unit (e.g., hours or days) if desired, or keep in seconds.

    Let's convert to hours for better readability.
    There are 3600 seconds in 1 hour.

    t1/2=40764.70588 s3600 s/hrt_{1/2} = \frac{40764.70588 \text{ s}}{3600 \text{ s/hr}} t1/2≈11.3235 hrt_{1/2} \approx 11.3235 \text{ hr}

    The half-life of the element is approximately 40765 seconds or 11.32 hours.

    40765 s or 11.32 hr\text{40765 s or 11.32 hr}
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