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The table for Vs(V) and I(mA) is empty. Perform the experiment, collect data, and then perform the following actions: (i) Plot the graph of voltage, Vs, on the vertical axis against current, I, on the

Physics

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R\text{R}

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The questions (a) through (h) describe the experimental procedure to collect data. Since the table for Vs(V)V_s(V) and I(mA)I(mA) is empty, I cannot perform the experiment or provide specific numerical answers for parts (i) and (j). However, I can explain how you would approach these steps.

i) Plot the graph of voltage, VsV_s, on the vertical axis against current, II, on the horizontal axis.

To plot the graph:

  1. Set up axes.* Draw a horizontal axis for current II (in Amperes, A) and a vertical axis for voltage VsV_s (in Volts, V).

    Remember to convert the current readings from milliamperes (mA) to amperes (A) by dividing by 1000 (e.g., 10 mA=0.01 A10 \text{ mA} = 0.01 \text{ A}).

  2. Choose a suitable scale.* Select scales for both axes that allow all your data points to fit and spread out well across the graph paper.

  3. Plot the data points.* For each pair of (I,Vs)(I, V_s) values from Table 1, mark a point on your graph.

  4. Draw the line of best fit.* Draw a straight line that passes as close as possible to most of the plotted points.

    This line should also pass through the origin (0,0)(0,0) if the resistor is ohmic.

    j) Determine the slope, KK, of the graph.

  5. Select two points on the line of best fit.* Choose two points on the straight line you drew, preferably far apart, that are easy to read.

    Let these points be (I1,V1)(I_1, V_1) and (I2,V2)(I_2, V_2).

  6. Calculate the slope.* The slope KK is calculated using the formula

    K=ΔVΔI=V2−V1I2−I1K = \frac{\Delta V}{\Delta I} = \frac{V_2 - V_1}{I_2 - I_1}

    Ensure that VV is in Volts and II is in Amperes for the slope to be in Ohms.

    k) What does the slope, KK, represent?

    The slope, KK, of the voltage-current graph represents the resistance of the unknown resistor. According to Ohm's Law, V=IRV = IR, where VV is voltage, II is current, and RR is resistance. If you plot VV on the y-axis and II on the x-axis, the slope ΔVΔI\frac{\Delta V}{\Delta I} is equal to the resistance RR.
    The slope KK represents the resistance of the unknown resistor R\boxed{\text{R}}.

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