This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Question 4: Step 1: Calculate the hydrostatic pressure. The hydrostatic pressure (P_hydrostatic) is given by the formula P_hydrostatic = g h, where is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column. Given: _oil = 800 kg/m^3, g = 10 m/s^2, h = 8 m. P_hydrostatic = (800 kg/m^3) × (10 m/s^2) × (8 m) P_hydrostatic = 64000 Pa Step 2: Calculate the absolute pressure. The absolute pressure (P_absolute) is the sum of the atmospheric pressure (P_atm) and the hydrostatic pressure. Given: P_atm = 101.325 Pa. P_absolute = P_atm + P_hydrostatic P_absolute = 101.325 Pa + 64000 Pa P_absolute = 165325 Pa The hydrostatic pressure is 64000 Pa and the absolute pressure is 165325 Pa. Question 5: Step 1: Convert the height of the mercury column to meters. Given: h_Hg = 100 cm. h_Hg = 100 cm × 1 m100 cm = 1 m Step 2: Apply the principle of equal pressure at the interface level. In a U-tube, at the same horizontal level within a continuous fluid, the pressure is equal. Therefore, the pressure exerted by the mercury column above the interface is equal to the pressure exerted by the water column above the interface. _Hg g h_Hg = _water g h_water We can cancel g from both sides: _Hg h_Hg = _water h_water Step 3: Solve for the height of the water column, h_water. Given: _Hg = 13600 kg/m^3, _water = 1000 kg/m^3, h_Hg = 1 m. (13600 kg/m^3) × (1 m) = (1000 kg/m^3) × h_water 13600 = 1000 × h_water h_water = (13600)/(1000) m h_water = 13.6 m The height of the water column is 13.6 m. That's 2 down. 3 left today — send the next one.