⚡ UTME PHYSICS CHALLENGE – THINK HARD! ⚡ A particle of mass 2 kg is moving in a circular path of radius 0.5 m with a speed that increases uniformly from 4 m/s to 8 m/s in 2 s. What is the tangential acceleration of the particle? A. 1 m/s² B. 2 m/s² C. 4 m/s² D. 8 m/s² React with the emoji of the answer you think is correct! 👇

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Answer

B

Step-by-step solution

3 steps

  1. Identify the given values.

    Initial speed, u=4 m/su = 4 \text{ m/s}
    Final speed, v=8 m/sv = 8 \text{ m/s}
    Time taken, t=2 st = 2 \text{ s}

  2. Use the formula for tangential acceleration.

    Tangential acceleration (ata_t) is the rate of change of speed.

    at=v−uta_t = \frac{v - u}{t}

  3. Substitute the values and calculate.

    at=8 m/s−4 m/s2 sa_t = \frac{8 \text{ m/s} - 4 \text{ m/s}}{2 \text{ s}} at=4 m/s2 sa_t = \frac{4 \text{ m/s}}{2 \text{ s}} at=2 m/s2a_t = 2 \text{ m/s}^2

    The tangential acceleration of the particle is 2 m/s22 \text{ m/s}^2.

    The correct option is B.
    2 m/s2\boxed{\text{2 m/s}^2}

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