⚡ UTME PHYSICS CHALLENGE – THINK HARD! ⚡ A particle of mass 2 kg is moving in a circular path of radius 0.5 m with a speed that increases uniformly from 4 m/s to 8 m/s in 2 s. What is the tangential acceleration of the particle? A. 1 m/s² B. 2 m/s² C. 4 m/s² D. 8 m/s² React with the emoji of the answer you think is correct! 👇

Question

Asked on March 25, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-03-25T05:32:16.275Z

Step 1: Identify the given values. Initial speed, u = 4 m/s Final speed, v = 8 m/s Time taken, t = 2 s Step 2: Use the formula for tangential acceleration. Tangential acceleration (a_t) is the rate of change of speed. a_t = (v - u)/(t) Step 3: Substitute the values and calculate. a_t = 8 m/s - 4 m/s2 s a_t = 4 m/s2 s a_t = 2 m/s^2 The tangential acceleration of the particle is 2 m/s^2. The correct option is B. 2 m/s^2

Accepted Answer · 2026-03-25T05:32:16.275Z

Step 1: Identify the given values. Initial speed, u = 4 m/s Final speed, v = 8 m/s Time taken, t = 2 s Step 2: Use the formula for tangential acceleration. Tangential acceleration (a_t) is the rate of change of speed. a_t = (v - u)/(t) Step 3: Substitute the values and calculate. a_t = 8 m/s - 4 m/s2 s a_t = 4 m/s2 s a_t = 2 m/s^2 The tangential acceleration of the particle is 2 m/s^2. The correct option is B. 2 m/s^2

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