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A) Write and balance the equation for the reaction between carbon (IV) oxide and heated charcoal. b) State the role of aqueous sodium hydroxide in the set-up.

Chemistry

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Answer

a

CO2(g)+C(s)⟶2CO(g)\text{CO}_2\text{(g)} + \text{C(s)} \longrightarrow 2\text{CO(g)}

Step-by-step solution

2 steps

Here's the solution for question 15:

Part a· 2 steps

The reaction in the combustion tube involves carbon (IV) oxide (carbon dioxide) reacting with heated charcoal (carbon).

  1. Write the unbalanced equation.

    CO2(g)+C(s)⟶CO(g)\text{CO}_2\text{(g)} + \text{C(s)} \longrightarrow \text{CO(g)}

  2. Balance the equation.

    CO2(g)+C(s)⟶2CO(g)\boxed{\text{CO}_2\text{(g)} + \text{C(s)} \longrightarrow 2\text{CO(g)}}

Part b

The role of aqueous sodium hydroxide in the set-up.

Aqueous sodium hydroxide is a strong base that reacts with acidic gases. In this setup, it absorbs any unreacted carbon (IV) oxide (CO2_2), which is an acidic gas. This ensures that only the product gas (Gas X, which is carbon monoxide, CO) passes through.

The role of aqueous sodium hydroxide is to absorb the unreacted carbon (IV) oxide.

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