From your results and information given, calculate: (i) the Concentration of A in mol/dm3 (ii) the molar mass of H2x (iii) the atomic mass of x (iv) the percentage of x in H2x [Na=23, H=1, O=6]

Here's a step-by-step solution to your chemistry problem. First, let's clarify the given atomic masses. We are given Na = 23, H = 1, and O = b. Assuming 'b' is a handwritten '16', we will use O = 16. Given information: Average volume of A (H_2X) used (V_A) = 26.50 cm^3 Equation: 2NaOH + H_2X → Na_2X + 2H_2O Mass concentration of H_2X (acid A) = 4.9 g/dm^3 Solution B (NaOH) contains 2 g of NaOH per 500 cm^3 Volume of B (NaOH) used (V_B) = 25 cm^3 Atomic masses: Na = 23, H = 1, O = 16 (assumed) Step 1: Calculate the molar concentration of NaOH (solution B). First, find the molar mass of NaOH: M(NaOH) = Na + O + H = 23 + 16 + 1 = 40 g/mol Next, calculate the mass of NaOH in 1 dm^3: Mass concentration of NaOH = 2 g500 cm^3 × 1000 cm^31 dm^3 = 4 g/dm^3 Now, calculate the molar concentration of NaOH (C_B): C_B = Mass concentrationMolar mass = 4 g/dm^340 g/mol = 0.1 mol/dm^3 Step 2: Calculate the molar concentration of H_2X (solution A). From the balanced chemical equation, the mole ratio of H_2X to NaOH is 1:2. So, n_A = 1 and n_B = 2. We use the titration formula: (C_A V_A)/(n_A) = (C_B V_B)/(n_B) Rearrange to solve for C_A: C_A = (C_B V_B n_A)/(V_A n_B) Substitute the known values: C_A = (0.1 mol/dm^3) × (25 cm^3) × 1(26.50 cm^3) × 2 C_A = (2.5)/(53) = (5)/(106) mol/dm^3 C_A ≈ 0.0471698 mol/dm^3 Rounding to four significant figures: i) The Concentration of A in mol/dm^3 C_A = 0.04717 mol/dm^3 Step 3: Calculate the molar mass of H_2X. We are given the mass concentration of H_2X as 4.9 g/dm^3. We calculated its molar concentration (C_A) in Step 2. Molar mass of H_2X = Mass concentrationMolar concentration Molar mass of H_2X = 4.9 g/dm^35/106 mol/dm^3 Molar mass of H_2X = (4.9 × 106)/(5) = (519.4)/(5) = 103.88 g/mol Rounding to four significant figures: ii) The molar mass of H_2X Molar mass of H_2X = 103.9 g/mol Step 4: Calculate the atomic mass of X. The molar mass of H_2X is the sum of the atomic masses of its constituent atoms: Molar mass of H_2X = (2 × Atomic mass of H) + Atomic mass of X 103.88 g/mol = (2 × 1 g/mol) + Atomic mass of X Atomic mass of X = 103.88 - 2 = 101.88 g/mol Rounding to four significant figures: iii) The atomic mass of X Atomic mass of X = 101.9 g/mol Step 5: Calculate the percentage of X in H_2X. Percentage of X = Atomic mass of XMolar mass of H_2X × 100\% Percentage of X = 101.88 g/mol103.88 g/mol × 100\% Percentage of X ≈ 0.980747 × 100\% Rounding to four significant figures: iv) The percentage of X in H_2X Percentage of X = 98.07\% That's 2 down. 3 left today — send the next one.