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Explain the oxidation of a primary alcohol to a carboxylic acid, using ethanol as an example.

Chemistry

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Answer

CH3COOH\text{CH}_3\text{COOH}

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Here is an example of the oxidation of a primary alcohol to an aldehyde and then to a carboxylic acid:

Example: Oxidation of Ethanol

When ethanol (a primary alcohol) is oxidized using a strong oxidizing agent like acidified potassium dichromate (K2Cr2O7/H+\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+) or potassium permanganate (KMnO4\text{KMnO}_4), it first forms ethanal (an aldehyde), which is then further oxidized to ethanoic acid (a carboxylic acid).

  1. Oxidation of primary alcohol to aldehyde

    CH3CH2OH→K2Cr2O7/H+CH3CHO\text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+} \text{CH}_3\text{CHO}
    • Reactant: Ethanol (a primary alcohol)
    • Product: Ethanal (an aldehyde)
  2. Oxidation of aldehyde to carboxylic acid

    CH3CHO→K2Cr2O7/H+CH3COOH\text{CH}_3\text{CHO} \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+} \text{CH}_3\text{COOH}
    • Reactant: Ethanal (an aldehyde)
    • Product: Ethanoic acid (a carboxylic acid)

    Combining these, the overall reaction for the complete oxidation of ethanol to ethanoic acid is:

    CH3CH2OH→K2Cr2O7/H+CH3COOH\text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+} \boxed{\text{CH}_3\text{COOH}}
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