This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Identify the reactants and products. The reactants are sodium carbonate (Na_2CO_3) and hydrochloric acid (HCl). The products of the reaction between a carbonate and an acid are a salt, water, and carbon dioxide. In this case, the salt formed is sodium chloride (NaCl). Step 2: Write the unbalanced chemical equation. Na_2CO_3(aq) + HCl(aq) → NaCl(aq) + H_2O(l) + CO_2(g) Step 3: Balance the chemical equation. • Balance sodium (Na): There are 2 Na atoms on the left, so place a coefficient of 2 in front of NaCl on the right. Na_2CO_3(aq) + HCl(aq) → 2NaCl(aq) + H_2O(l) + CO_2(g) • Balance chlorine (Cl): Now there are 2 Cl atoms on the right, so place a coefficient of 2 in front of HCl on the left. Na_2CO_3(aq) + 2HCl(aq) → 2NaCl(aq) + H_2O(l) + CO_2(g) • Check hydrogen (H), carbon (C), and oxygen (O): H: 2 atoms on the left (from 2HCl) and 2 atoms on the right (from H_2O). Balanced. C: 1 atom on the left (from Na_2CO_3) and 1 atom on the right (from CO_2). Balanced. O: 3 atoms on the left (from Na_2CO_3) and 1 atom (from H_2O) + 2 atoms (from CO_2) = 3 atoms on the right. Balanced. The balanced chemical equation is: Na_2CO_3(aq) + 2HCl(aq) → 2NaCl(aq) + H_2O(l) + CO_2(g) That's 2 down. 3 left today — send the next one.