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Using Faraday's laws of electrolysis, calculate the number of moles (N) of a substance deposited with a valency (z) of 2, given a current (I) of 3 A for a time (t) of 400 s.

Chemistry

ScanSolve AI Answer

Answer

0.00622 mol\text{0.00622 mol}

Step-by-step solution

4 steps

Here's the solution based on the parameters provided in the image. The question "NE?" is interpreted as asking for the number of moles (NN) of the substance deposited.

Given Parameters from the image:

  • Time (tt) = 400 s
  • Current (II) = 3 A
  • Valency (zz) = 2 (This is the number of electrons per mole of substance)
  • Faraday's constant (FF) = 96500 C/mol
  • Relative Atomic Mass (RAM\text{RAM}) = 119 g/mol (This parameter is not needed to calculate NN using the current and time, but would be used if calculating mass deposited).

Formula to calculate moles (NN) from current and time:

N=I×tz×FN = \frac{I \times t}{z \times F}
  1. Substitute the given values into the formula.

    N=3 A×400 s2×96500 C/molN = \frac{3 \text{ A} \times 400 \text{ s}}{2 \times 96500 \text{ C/mol}}
  2. Perform the multiplication in the numerator.

    N=1200 C2×96500 C/molN = \frac{1200 \text{ C}}{2 \times 96500 \text{ C/mol}}
  3. Perform the multiplication in the denominator.

    N=1200 C193000 C/molN = \frac{1200 \text{ C}}{193000 \text{ C/mol}}
  4. Calculate the final value for NN.

    N≈0.0062176 molN \approx 0.0062176 \text{ mol}

    Rounding to a reasonable number of significant figures (e.g., three, based on the input values):

    N≈0.00622 molN \approx 0.00622 \text{ mol}

    The number of moles (NN) of the substance deposited is 0.00622 mol\boxed{\text{0.00622 mol}}.

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