during electrolysis 5g of a metal E was deposited by passing a current of 200Ampere for 30mins across the solution of E. find the ionic charge of E

March 25, 2026Physics

ScanSolve AI Answer

March 25, 2026

Answer

30 min \times 60 s/min = 1800 \text{ s}$$

To solve this problem, we need to use Faraday's laws of electrolysis. Faraday's laws relate the amount of substance deposited during electrolysis to the quantity of electricity passed through the solution.

Step 1: Calculate the total charge ( $Q$ ) passed. The current ( $I$ ) is $200 \text{ A}$ . The time ( $t$ ) is $30 \text{ minutes}$ . We need to convert this to seconds. $t = 30 min \times 60 s/min = 1800 \text{ s}$ The total charge ( $Q$ ) is given by the formula: $Q = I \times t$

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Faraday's laws relate the amount of substance deposited during electrolysis to the quantity of electricity passed through the solution.

Asked on March 25, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 25, 2026

To solve this problem, we need to use Faraday's laws of electrolysis. Faraday's laws relate the amount of substance deposited during electrolysis to the quantity of electricity passed through the solution. Step 1: Calculate the total charge (Q) passed. The current (I) is 200 A. The time (t) is 30 minutes. We need to convert this to seconds. t = 30 min × 60 s/min = 1800 s The total charge (Q) is given by the formula: Q = I × t Q = 200 A ×