Given P(2, 5) and the translation vector r = -3 8 .

Given $P(2, 5)$ and the translation vector $r = \begin{pmatrix} -3 \\ 8 \end{pmatrix}$.

The image of $P(2, 5)$ is:

ii)

Given $Q(-4, -6)$ and the translation vector $r = \begin{pmatrix} -3 \\ 8 \end{pmatrix}$.

The image of $Q(-4, -6)$ is:

2b)

Total profit = GH¢ 9,000.00.
Richard's manager share = $\frac{1}{3} \times \text{GH¢ } 9,000.00 = \text{GH¢ } 3,000.00$.

Remaining profit = Total profit - Richard's manager share
Remaining profit = GH¢ $9,000.00 - \text{GH¢ } 3,000.00 = \text{GH¢ } 6,000.00$.

Joyce's contribution = GH¢ 10,000.00.
Richard's contribution = GH¢ 5,000.00.
Ratio of contributions (Joyce : Richard) = $10,000 : 5,000 = 2 : 1$.
Total ratio parts = $2 + 1 = 3$.

i)

Joyce's share = $\frac{2}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 4,000.00$.
Joyce received:

ii)

Richard's share = $\frac{1}{3} \times \text{GH¢ } 6,000.00 = \text{GH¢ } 2,000.00$.

Richard's total earnings = Richard's manager share + Richard's share from remaining profit
Richard's total earnings = GH¢ $3,000.00 + \text{GH¢ } 2,000.00 = \text{GH¢ } 5,000.00$.
Richard received in total:

3a)

Original daily wage = GH¢ 25.00.
Increase = $10\%$ of GH¢ $25.00 = 0.10 \times \text{GH¢ } 25.00 = \text{GH¢ } 2.50$.
New daily wage = GH¢ $25.00 + \text{GH¢ } 2.50 = \text{GH¢ } 27.50$.

Number of days worked = 30 days.
Total amount paid = New daily wage $\times$ Number of days worked
Total amount paid = GH¢ $27.50 \times 30 = \text{GH¢ } 825.00$.
Asana will be paid:

3b)

The total length of the top side is $8 \text{ m}$. The bottom right segment is $3 \text{ m}$.
The missing bottom left segment is $8 \text{ m} - 3 \text{ m} = 5 \text{ m}$.
The total height of the left side is $5 \text{ m}$. The right vertical segment is $3 \text{ m}$.
The missing inner vertical segment is $5 \text{ m} - 3 \text{ m} = 2 \text{ m}$.

i)

The perimeter is the sum of all outer sides: $8 \text{ m} + 5 \text{ m} + 3 \text{ m} + 2 \text{ m} + 5 \text{ m} + 3 \text{ m}$.
Perimeter = $8 + 5 + 3 + 2 + 5 + 3 = 26 \text{ m}$.
The perimeter is:

ii)

Divide the shape into two rectangles.
Rectangle 1 (top): $8 \text{ m} \times 3 \text{ m} = 24 \text{ m}^2$.
Rectangle 2 (bottom left): $5 \text{ m} \times 2 \text{ m} = 10 \text{ m}^2$.
Total Area = Area 1 + Area 2 = $24 \text{ m}^2 + 10 \text{ m}^2 = 34 \text{ m}^2$.
The area is:

iii)

Cost per square metre = GH¢ 20.00.
Total area = $34 \text{ m}^2$.
Total cost = Total Area $\times$ Cost per square metre
Total cost = $34 m^2 \times GH¢ 20.0