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A plan of a house is drawn to a scale of 2:1000. A room in the house is 6m long. The length of the room on the map is: The y-intercept of a line is -5 and the gradient is -3. The equation of the line

Mathematics

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Graph of y = −3x − 5

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Key points of y = −3x − 5
Pointxy
x-intercept−1.670
y-intercept0−5

Step-by-step solution

17 steps

Here are the solutions to the problems:

23. A plan of a house is drawn to a scale of 2:1000. A room in the house is 6m long. The length of the room on the map is:

  1. Convert the real length of the room from meters to centimeters.

    6 m=6×100 cm=600 cm6 \text{ m} = 6 \times 100 \text{ cm} = 600 \text{ cm}
  2. Apply the given scale of 2:1000.

    This means 2 units on the map represent 1000 units in real life.

    Length on mapActual length=21000\frac{\text{Length on map}}{\text{Actual length}} = \frac{2}{1000}
  3. Substitute the actual length and solve for the length on the map.

    Length on map600 cm=21000\frac{\text{Length on map}}{600 \text{ cm}} = \frac{2}{1000} Length on map=21000×600 cm\text{Length on map} = \frac{2}{1000} \times 600 \text{ cm} Length on map=12001000 cm\text{Length on map} = \frac{1200}{1000} \text{ cm} Length on map=1.2 cm\text{Length on map} = 1.2 \text{ cm}

    The length of the room on the map is 1.2 cm.
    The correct option is [B] 1.2cm.

    24. The y-intercept of a line is -5 and the gradient is -3. The equation of the line is:

  4. Recall the general equation of a straight line, which is y=mx+cy = mx + c, where mm is the gradient and cc is the y-intercept.

  5. Substitute the given values for the gradient (m=−3m = -3) and the y-intercept (c=−5c = -5) into the equation.

    y=(−3)x+(−5)y = (-3)x + (-5) y=−3x−5y = -3x - 5

    The equation of the line is y = -3x - 5.
    The correct option is [D] y = -3x - 5.

    25. The coordinates of the midpoint of the straight line joining the points M(4,y)M(4, y) and N(−6,4)N(-6, 4) is P(−1,2)P(-1, 2). The value of yy is:

  6. Recall the midpoint formula for two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), which is P(x1+x22,y1+y22)P\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right).

  7. We are given the points M(4,y)M(4, y) and N(−6,4)N(-6, 4), and the midpoint P(−1,2)P(-1, 2).

    We need to find the value of yy. We will use the y-coordinate part of the midpoint formula.

    yP=yM+yN2y_P = \frac{y_M + y_N}{2}
  8. Substitute the given y-coordinates into the formula.

    2=y+422 = \frac{y + 4}{2}
  9. Solve for yy.

    2×2=y+42 \times 2 = y + 4 4=y+44 = y + 4 y=4−4y = 4 - 4 y=0y = 0

    The value of yy is 0.
    The correct option is [D] 0.

    26. Given that m−nx=y\frac{m-n}{x} = y, then expressing nn in terms of m,ym, y and xx gives?

  10. Start with the given equation.

    m−nx=y\frac{m-n}{x} = y
  11. Multiply both sides by xx to eliminate the denominator.

    m−n=xym-n = xy
  12. Subtract mm from both sides to isolate the term with nn.

    −n=xy−m-n = xy - m
  13. Multiply both sides by −1-1 to solve for nn.

    n=−(xy−m)n = -(xy - m) n=−xy+mn = -xy + m n=m−xyn = m - xy

    Expressing nn in terms of m,ym, y and xx gives n = m - xy.
    The correct option is [C] m - xy.

    27. Given that x+2y=5x + 2y = 5 and x−2y=8x - 2y = 8. Then the value of 4x4x is:

  14. Write down the given system of equations.

    1. x+2y=5x + 2y = 5
    2. x−2y=8x - 2y = 8
  15. Add equation (1) and equation (2) to eliminate yy.

    (x+2y)+(x−2y)=5+8(x + 2y) + (x - 2y) = 5 + 8 x+2y+x−2y=13x + 2y + x - 2y = 13 2x=132x = 13
  16. Solve for xx.

    x=132x = \frac{13}{2}
  17. Calculate the value of $4x$.

    4x=4×1324x = 4 \times \frac{13}{2} 4x=2×134x = 2 \times 13 4x=264x = 26

    The value of 4x4x is 26\boxed{\text{26}}.

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